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0=20x^2-33x-23
We move all terms to the left:
0-(20x^2-33x-23)=0
We add all the numbers together, and all the variables
-(20x^2-33x-23)=0
We get rid of parentheses
-20x^2+33x+23=0
a = -20; b = 33; c = +23;
Δ = b2-4ac
Δ = 332-4·(-20)·23
Δ = 2929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{2929}}{2*-20}=\frac{-33-\sqrt{2929}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{2929}}{2*-20}=\frac{-33+\sqrt{2929}}{-40} $
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